Answer:
Step-by-step explanation:
-(4q+8) + 6q = 12q - 5/6(18q + 6)
Open brackets:
<=> - 4q - 8 + 6q = 12q - 5/6*18q - 5/6*6
<=> - 4q - 8 + 6q = 12q - 15q - 5
Put q in one side and non q in one side:
<=> - 4q + 6q - 12q + 15q = 8 - 5
<=> 5q = 3
<=> q = 3/5
Answer:
First Problem. 17x , 17 + x, and 7x + 10x
Second Problem. 2 + 12y, 2x1 + 2x6y
Step-by-step explanation:
You have to find the greatest common factor GCF for each number, you can do it for both at the same time:
foot ---- hand
GCF 48 60
2 24 30
2 12 15
3 4 5
From here you dont have more numbers (GCF) for this pair, now for finding the greatest number of identical kits multiply the GCFs: 2*2*3=12 you have 12 kits containing 4 foot-warmer packets and 5 hand-warmer packets (from table the last row in foot and hand)
Answer:
Common difference = 2
First term = 3.
Step-by-step explanation:
3rd term = a1 + (3 - 1)d = 7 where a1 = first term and d = the common difference.
Sum of the first 12 terms = (12/2)[2a1 + (12-1)d] = 168
so 6(2a1 + 11d) = 168
So simplifying, we have the following system:
a1 + 2d = 7 ..................(A)
12a1 + 66d = 168
2a1 + 11d = 28.................(B) Multiplying equation A by - 2:
-2a1 - 4d =- -14 Adding this to equation B
7d = 14
d = 2
Now plug this into equation A:
a1 + 2(2) = 7
a1 = 7-4
a1 = 3.
