Answer:
Step-by-step explanation:
An eigenvalue of n × n is a function of a scalar
considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =
Suppose the matrix ![A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%26-1%5C%5C2%261%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Thus, the equation of the determinant (A -
1) = 0
This implies that:
![\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%5Clambda%20%26-1%5C%5C2%261-%20%5Clambda%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%3D0)



Hence, the eigenvalues of the equation are 
Also, the eigenvalues can be said to be complex numbers.
125 would be the correct answer unless you needed to round then it would be 126
Look on Google or ask your teacher
The answer is 2 and 8.5 over 10.