Can someone please answer. There is one problem. Thank you!
1 answer:
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I think your teacher may have made a typo. Refer to the diagram below. If we ignore segment ZA for now, we can see a rectangle forms with angle W = angle Y = 90. Also, we can see that WX = 6 is the horizontal base and WZ = 8 is the vertical height.
However, the side opposite WZ (which is XY) should also be 8 cm tall, and not 6 cm. If XY was 6 cm, then point Y would move to where point A is located (and the quadrilateral would be WXAZ instead of WXYZ). This new quadrilateral would not have a 90 degree angle at point Y's new location.
In other words, if we want angle Y to be 90 degrees, then side XY must be 8 units long. I have a feeling this is where the typo is, but your teacher might have been intending to say something else.
Step-by-step explanation:
Hey there!
The coordinates of a triangle are;
- A (1,2)
- B (1,-2)
- C (-2,-2)
- Scale factor = -4 and centre at (0,0)
Now, We have;
P(x,y)----------- P'(kx, ky)
<u>Keep</u><u> </u><u>formula</u><u>;</u>
<u>A</u><u>(</u><u>1</u><u>,</u><u>2</u><u>)</u><u>----------</u><u> </u><u>A'</u><u>(</u><u>-4</u><u>×</u><u>1</u><u> </u><u>,</u><u>-4</u><u>×</u><u>2</u><u>)</u>
= A'(-4, -8)
B(1,-2)------------- B'(-4,8)
C(-2,-2)-------------C'(8,8)
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<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
