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Colt1911 [192]
2 years ago
9

Help? I missed 3 days of school ;-;

Chemistry
2 answers:
Mariulka [41]2 years ago
8 0
Ill get you started: 3 is 1,1,2.  

You gotta learn how to do this tho fam

Just multiply each reactant/product by some number until you get the same number of each atom on both sides.  Its like an easy math problem, but people get scared when they see letters.  U got this homes

ludmilkaskok [199]2 years ago
8 0
Wow that's terrible. But I don't know the answer. Hope you find help fast. Bye.☺️ ✌️
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Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?
Georgia [21]

<u>Answer:</u> The correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.  

The balanced molecular equation is:

Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)

The complete ionic equation follows:

Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

Hence, the correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

7 0
3 years ago
3. What molecule or ion acts as the nucleophile in the base-catalyzed reaction between acetic anhydride and vanillin? A. Vanilli
Effectus [21]

Answer:

B

B

A

C

Explanation:

3

B. Vanillin as a phenoxide ion (conjugate base)

4

B. Protonation of acetic anhydride

5

A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride

6

C. 1 mmol of vanillin and 10.6 mmol acetic anhydride

8 0
2 years ago
The so-called Livestock Evolution involves increased consumption of animal products in developing countries.
Rama09 [41]
This is probably true but I’m not 100% sure
4 0
2 years ago
If earth is 1.50 x 10^8km from the sun what is the distance in Mm?
Readme [11.4K]

The distance of the earth to the sun in Mm = 1.5 x 10⁵

<h3>Further explanation</h3>

Given

The distance of the earth to the sun : 1.50 x 10⁸ km

Required

The distance in Mm

Solution

In converting units we must pay attention to the conversion factor.

the conversion factor :

1 kilometer(km) = 10⁻³ megameter(Mm)

So the distance conversion :

1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm

8 0
2 years ago
Question 3 of 6
Bond [772]

Answer:

c,d,e

Explanation:

3 0
3 years ago
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