Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
<u>Answer:</u> The
for the reaction is -1835 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction follows:

The intermediate balanced chemical reaction are:
(1)
( × 4)
(2)

The expression for enthalpy of the reaction follows:
![\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B4%5Ctimes%20%28-%5CDelta%20H_1%29%5D%2B%5B1%5Ctimes%20%5CDelta%20H_2%5D)
Putting values in above equation, we get:

Hence, the
for the reaction is -1835 kJ.
Answer:
281s
Explanation:
Given parameters:
Speed of the scooter = 1.45min per mile
Fuel economy of engine = 85miles per gallon
Quantity of fuel = 145mL
Unknown:
Time of travel with the volume of fuel given = ?
Solution:
To solve this problem, we need to find the distance the fuel will last.
Rate of fuel consumption by the engine = 85miles per gallon
Convert 145mL to gallons;
3785.41mL = 1 gallon
145mL will therefore give
= 0.038gallons
So;
Distance covered = 85miles per gallon x 0.038gallons = 3.23miles
From;
Rate of travel =
Time = rate of travel x distance = 1.45 minutes per mile x 3.23miles
Time = 4.7min
1 min = 60s
4.7min = 4.7 x 60 = 281s
Though she hits the drum, the papers on the drum also vibrate.
This is due to the fact that when she hits the drum, the shock waves created by the hitting travel through the skin of the drum and radiate outwards. When they encounter the papers, some of this energy is transmitted to the papers and the papers also vibrate.