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Llana [10]
3 years ago
11

A sample of table sugar (sucrose c12h22o11) has a mass of 3.115 g

Chemistry
1 answer:
attashe74 [19]3 years ago
6 0
Hey there:

a) atomic mass:

Carbon =<span>12.0107 g/mol

</span>Hydrogen = <span>1.00794 g/mol

Oxygen =  </span><span>15.9994 g/mol
</span>
Therefore:


C12H22O11 = 


12 * 12.0107 + 1 * 1.00794 + 16 * 15.9994 => <span>342.29648 g/mol

__________________________________________________________


b) number of moles:

n = m / mm

n = 3.115 / </span><span>342.29648 

n = 0.0091 moles

________________________________________________

hope this helps!</span>
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How many molecules of carbon dioxide are in 5.61 moles of carbon dioxide (CO2)?
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<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂

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