Answer:
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 6.4 L of nitrogen monoxide gas
Explanation:
Equation of reaction: 4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)
From the equation of reaction, 5 moles of oxygen gas produces 4 moles of nitrogen monoxide gas
1 mole of a gas at STP occupies a volume of 22.4 L
5 moles of oxygen gas occupies a volume of 5 * 22.4 L = 112 L
4 moles of nitrogen monoxide as occupies a volume of 4 * 22.4 L = 89.6 L
Therefore, 89.6 L of nitrogen monoxide gas are produced from 112.0 L of oxygen
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 8.0 * (89.6/112
Moles of nitrogen monoxide gas produced from 8.0 L of oxygen gas = 6.4 L of nitrogen monoxide gas
One thing to remember is homo=same/pure and hetero=different
so heterogeneous mixture is would be salad, vegetable soup, trail mix and brass.
this is because salad, vegetable soup, trail mix, and brass have a lot components and they’re not pure.
Hopefully i could help!!
<h3>1. <u>Answer;</u></h3>
Percentage yield = 65.9%
<h3><u>Explanation;</u></h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
Therefore;
- Percentage yield = Actual yield/theoretical yield × 100%
= (1.20 g/1.82 g) × 100%
= 65.9%
<h3 /><h3>2. <u>Answer;</u></h3>
The amount of measured yield over calculated yield
<h3>Explanation;</h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
- The actual yield is the actual amount produced when the experiment or reaction is carried out.
- Theoretical yield is the calculated or expected amount of the product. It is based on the limiting reactant.
<h3>3. <u>Answer</u>;</h3>
= 37.71 g
<h3><u>Explanation;</u></h3>
The balanced equation is:
2 Na + Cl₂ → 2 NaCl.
From the balanced equation:
2.0 moles of Na reacts with 1.0 mole of chlorine gas to give 2.0 moles of NaCl.
- The number of moles of Na = mass/atomic mass),
n = (17.25 g / 22.989 g/mole of Na)
= 0.75 moles
Thus;
- Using cross multiplication and from the equation:
2.0 moles of Na → 2.0 moles of NaCl
0.75 moles of Na → 0.75 moles of NaCl
Therefore;
- The mass of the produced NaCl (m = n x molar mass)
m = (0.75 mole x 58.443 g/mole of NaCl)
= 43.85 g.
- This is the yield if the percentage of yield is 100%, but the percentage yield of the reaction is 86%.
Hence;
The actual yield = (43.85 g) (86/100)
= 37.71 g.
<h3>4. <u>Answer;</u></h3>
Oxygen and hydrogen molecules will mix because of random movement of their molecules.
<h3><u>Explanation;</u></h3>
- Both gasses will diffuse into the other jar until the molecules are well distributed into both containers.
- Diffusion is the movement of molecules from a point of high concentration to areas of low concentration until equilibrium is attained.
- The mixture of gases will have a partial pressure that is equal to the sum of the partial pressures of the component gases.
Answer:
copper
Explanation:
its an element, its not mixed with anything else
Answer:
8.61 mL of the HCl solution
Explanation:
The reaction that takes place is:
- 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:
- 4x10² mg = 400 mg = 0.400g
- 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
- 6.859*10⁻³ mol Mg(OH)₂ *
3.429x10⁻³ mol HCl
Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:
= [H⁺]
- 0.0398 M = [H⁺] = [HCl] *Because HCl is a strong acid*
Thus, the volume is:
- 0.0398 M = 3.429x10⁻³mol HCl / Volume
- Volume = 8.616x10⁻³ L = 8.62 mL
