<u>Given:</u>
Volume of gas = 215 ml
Initial temperature T1 = 20C = 20 +273 = 293 K
Initial pressure P1 = 1 atm
Final pressure P2 = 1.5 atm
<u>To determine:</u>
The final temperature T2
<u>Explanation:</u>
Based on Gay-Lussac's Law:
P α T
Therefore we have the relation:
P1/T1 = P2/T2
T2 = P2T1/P1 = 1.5 *293/1 = 439.5 K
Converting from Kelvin to degrees C we have:
T2 = 439.5 - 273 = 166.5 C
Ans: The final temperature is 439.5 K or 166.5 C
It will always have a greater mass
Answer:
for the molecule with no dipole moment = 1,2dibromo ethane
for the molecule with dipole moment = 1,1 dibromo ethane
Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)