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hram777 [196]
2 years ago
11

Solve the following quadratic equation by factoring:

y^{2}" alt="y^{2}" align="absmiddle" class="latex-formula">-8y=0
Mathematics
1 answer:
Furkat [3]2 years ago
4 0

Answer:

y = 8 or y = 0

Step-by-step explanation:

Solve for y over the real numbers:

y^2 - 8 y = 0

Factor y from the left hand side:

y (y - 8) = 0

Split into two equations:

y - 8 = 0 or y = 0

Add 8 to both sides:

Answer: y = 8 or y = 0

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using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


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3 years ago
Solve the quadratic equation by factoring: 15x^2+4x-4=0
joja [24]
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15*-4 = -60

Now we need to split the b term into two pieces that multiply to -60 and add to 4.

-6 and 10 will work.

Now group one part of b with the 15x^2 and the other part with -4.

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Now factor both terms.

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