2 years ago

I need help with all of them.. please help..

Chemistry

1 answer:

Crazy boy [7]2 years ago

7 0

The answer is not the alphabet

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Sodium Sulfide chemical formula

Yanka [14]

Answer:

Na2S

Explanation:Just took the test

8 0

3 years ago

I have no idea how to do this and need help

den301095 [7]

Answer:

60.55%

Explanation:

nO3=155/48

nO2 used: 3/2nO3=4.84375

percent yield: 4.84375/8=60.55%

5 0

3 years ago

7.895 g + 3.4 g round to the correct number significant figures

DIA [1.3K]

Answer:

11.3 g

Explanation:

7.895 + 3.4 = 11.295

When rounded to correct number of significant figures --> 11.3

There are 3 significant figures in 11.3

7 0

2 years ago

A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve

jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

$V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL$

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

$d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL$

Therefore, density of metal is 19.33 g/mL.

3 0

3 years ago

if 15 mol C is mixed with 10 mol O2 which reactant is the limiting reactant? Which reactant would be the excess reactant?

ioda

Answer:

C is the excess reactant.

Explanation:

Reaction is C + O2 --> CO2

1mol of C required to react with 1mol O2

Therefore 15 - 10 = 5moles of C will be in excess

6 0

3 years ago