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icang [17]
3 years ago
8

What volume of a 1.3 M solution of Na2CO3 can be made from 800 ml. of a 4.9

Chemistry
1 answer:
galben [10]3 years ago
4 0
2.5 m that’s the answer yessir
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If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?
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Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:

ee = (R – S) * 100%

 

Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:

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Summary of answers:

R = major enantiomer = 0.875 or 87.5%

<span>S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%</span>

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