2NO + O₂ = 2NO₂
V(O₂)=10.5 L
V(NO₂)=2V(O₂)
V(NO₂)=2*10.5=21.0 L
21.0 liters of NO2 are produced
Answer:
Tides . hope this helps
Explanation:
the tidal force causes earth and its water to bulge out on the side closest to the moon
x = = 0.50 M
Answer:
In order to produce some SbCl5, a 1.00 mole sample of SbCl3 is first placed in an empty 2.00 liter container maintained at a temperature different from 182oC. At this temperature, Kc, equals 0.117. How many moles of Cl2 must be added to this container to reduce the number of moles of SbCl3 to 0.700 mole at equilibrium
Moles Cl2 that must be added = 0.40 mol
Explanation:
K = ( = 0.117
Equilibrium concentrations:
= (1.00 - 0.70) mol / 2.00 L = 0.15 M <<---why is it 1.00-0.70???
= 0.700 mole / 2.00L = 0.350 M
= x
Kc = ÷ (0.15) = 0.117
Moles Cl2 at equilibrium = 0.050 mol L x 2.00 L = 0.10 mol
Moles Cl2 needed to make 0.300 mol SbCl3 into SbCl5 = 0.30 mol
Moles Cl2 that must be added = 0.40 mol
Answer:
Kp = 0.35 & Kc = 0.0075
Explanation:
PCl₅ ⇄ PCl₃ + Cl₂
Initial(atm) 0.5 0 0
At equilibrium 0.5 - p p p
- Total pressure at equilibrium = 0.78
- 0.5 - p + p + p = 0.78
- p = 0.28
So partial pressure of PCl₅ = 0.5 - 0.28 = 0.22 atm
Similarly PCl₃ = 0.28 atm & Cl₂ = 0.28 atm
According to law of mass action
- Kp =
- Kp =
- Kp = 0.35
We know Kp = Kc x (RT)Δng
Δng = change in gaseous moles
= product moles - reactant moles
= 2 - 1
= 1
R = universal gas constant = 0.0821 lit. atm. mol⁻¹. K⁻¹
So Kc =
= 0.0081