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Fed [463]
3 years ago
7

Question 1:

Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:

1.a

2.c

hope helps

Explanation:

mark

pa

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Please please please help please
denpristay [2]
Hydrogen and oxygen! Happy holidays btw
3 0
3 years ago
What is the temperature -71 oC expressed in Kelvin?<br> Group of answer choices
satela [25.4K]

Answer: 202.15

Explanation:

-71°C + 273.15

= 202.15K

5 0
3 years ago
A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0
larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = ?

n = number of moles of gas  = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 25^oC=273+25=298K

V_1 = initial volume of gas  = 25 mL

V_2 = final volume of gas  = 75 mL

Now put all the given values in the above formula, we get:

w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})

w=2.722J

Therefore, the work done by the system is, 2.2722 J

8 0
3 years ago
Which ones are all renewable resources?
9966 [12]
D, they can be renewed quickly rather than non renewables in which nonrenewable take millions of years. Biomass is all around us, so is water (hydro) and the sun is around us too. 
3 0
3 years ago
Read 2 more answers
The complete combustion of a sample of propane produced 2.641 grams of carbon dioxide and 1.442 grams of water as the only produ
ohaa [14]
A general equation for a combustion reaction would be expressed as follows:

CxHy + (x+y/2)O2 = xCO2 + y/2H2O

Propane would obviously would only have carbon and hydrogen in its structure. Assuming a complete combustion, all of the carbon atoms would go to carbon dioxide and all of the hydrogen atoms to water. To determine the empirical, we determine the number of carbon and hydrogen atoms present.

moles C = 2.461 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.06 mol C

moles H = 1.442 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H ) = 0.16 mol H

Then, we divide the smallest amount to the each mole of the atoms. We do as follows:

C = 0.06 / 0.06 = 1
H = 0.16 / 0.06 = 2.67

Then we multiply a number in order to obtain a whole number ratio between the atoms.

1        CH2.67
2       C2H5.34
3       C3H8   <-------- empirical formula
8 0
3 years ago
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