Ask question

Ask question

All categories

ICE Princess25 [194]

1 year ago

15

use the protractor photo to find the measure of each of the following angles

tless%20%5C%20%20abd" id="TexFormula1" title=" \ \textless \ abd" alt=" \ \textless \ abd" align="absmiddle" class="latex-formula">

1 answer:

SashulF [63]1 year ago

3 0

You have to read the protractor to determine the measure of each angle.

For all the angles B is the vectress.

∠ABF =90º

∠ABE= 40º

∠ABD= 20º

∠EBF= ∠ABF-∠ABE= 90º-40º= 50º

∠DBE= ∠ABE-ABD= 40º-20º=20º

You might be interested in

Which statement is true? (with explanation)

Art [367]

The function has neither because it goes infinitely up and infinitely down

7 0

3 years ago

Y – 4 = 20 A. The difference between a number and 4 is 20. B. The product of a number and 4 is 20. C. A number combined with 4 i

Rama09 [41]

Answer:

A

Step-by-step explanation:

Subtraction means "difference". The only choice there that has the word "difference" in it is choice A.

3 0

3 years ago

Find the unknow based length of triangle A=31.5 in 2 H=7 in then wat is Abe

Sauron [17]

Answer:

the answer is 9

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Can three segments with lengths 8, 15, and 6 make a triangle?

butalik [34]

Yes, not a equallateral but an issoceles

5 0

3 years ago