Answer:
14.3 g SO₃
Explanation:
2S + 3O₂ → 2SO₃
First, find the limiting reactant. To do that, calculate the mass of oxygen needed to react with all the sulfur.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (3 mol O₂ / 2 mol S) = 0.268 mol O₂
0.268 mol O₂ × (32 g O₂ / mol O₂) = 8.57 g O₂
There are 10.0 g of O₂, so there's enough oxygen. The limiting reactant is therefore sulfur.
Use the mass of sulfur to calculate the mass of sulfur trioxide.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (2 mol SO₃ / 2 mol S) = 0.178 mol SO₃
0.178 mol SO₃ × (80 g SO₃ / mol SO₃) = 14.3 g SO₃
Answer:
24 moles
Explanation:
given data
= 48 grams
to find out
how many moles of 
will be produced
solution
we know that Stoichiometry is here as
......................1
so we get here mole of solute that is express as
mole = 
..........................2
put here value for
mole = 
mole of = 24 mole
and
we can say that here as per equation 1 that one mole of is go with one mole of
so here 24 mole is go with 24 moles mole of
so we can say will be produced 24 moles
The answer should be the last one Line graph. I hope I helped!
Nitric acid does NOT react with water, water disassociates the molecules into those ions (above). ... Water,Being a polar solvent,…makes HNO3 ionise or dissociate or simply break down into Hydronium ions, i.e,H+ or H3O+ ions and nitrate NO3- ions..that's all.
-Google
<u>Answer</u>:-
When the reaction takes place Ca is reduced or is an oxidizing agent.
Reaction:
Ca + 2Cl =CaCl2
Note: There is a +2 charge on Ca(Calcium) and -1 charge on each Cl-atom(Chlorine atom) hence the charges are cancelled. Therefore, the total charge on the whole compound is zero.
Explanation:-
• Reduction: gain of electron/electrons
gain of hydrogen
loss of oxygen
Oxidation: gain of oxygen
loss of hydrogen
loss of electron/electrons.
• Oxidizing agent/reduced
Reducing agent/oxidized
• The molecule that is oxidized loses an electron and the molecule that is reduced gains the electron that was lost by the oxidized molecule.
