<h3>Given:</h3>
M₁ = 2.0 mol/L
V₁ = 1 L
M₂ = 0.1 mol/L
<h3>Required:</h3>
V₂
<h3>Solution:</h3>
M₁V₁ = M₂V₂
V₂ = M₁V₁ / M₂
V₂ = (2.0 mol/L)(1 L) / (0.1 L)
<u>V₂ = 20 L</u>
Therefore, the volume of the new solution will be 20 L.
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Work out the number of moles in
100.00 grams of the oxide.
For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:
36.84 g N14.0067 g N/mol N=2.630 mol N
For oxygen: The atomic mass of O is
15.9994, and we have
100.00−36.84=63.16 g O:
63.16 g N 15.9994 g N/mol N=3.948 mol N
Now the ratio 3.958 2.630 is very close to
1.5=32
. So we conclude that the gas has three moles
O to two moles N making the empirical formula
N2O3.
<h2>
<u>Mark as Brainliest</u></h2>
A. When the substance is in its gaseous state.
<u>Explanation:</u>
When a substance is expanding against its constant volume and pressure, its temperature increases except when the substance is in gaseous state and not in liquid or solid state. So the internal energy increase in the system not only increases and maintaining the volume and pressure of the system remains constant in its gaseous phase. In the first law of Thermodynamics, it is used specifically that to especially in the case of gaseous system.
<u></u>
I would say true because the Valence Shell Electron Pairs will Repel each other. When they do they are forced to the opposite side of the Carbon atom giving CO2 a linear molecular shape. The CO2 bond angle will be 180 degrees since it has a linear molecular geometry.
sorry if im wrong
