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Paul [167]
4 years ago
11

If a liquid has a volume of 5800 mL and you need the mass in Liters, will the number appear to

Chemistry
1 answer:
Natali [406]4 years ago
6 0

Answer:

The number will appear to become smaller (from 5800 mL to 5.8 L).

Explanation:

The conversion of milliliters to liters is the following:

1 L = 1000 mL

Hence, the volume of 5800 mL to L is:

V = 5800 mL*\frac{1 L}{1000 mL} = 5.8 L      

Therefore, the number will appear to become smaller (from 5800 mL to 5.8 L).

I hope it helps you!

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Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

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3 years ago
Formation of magnesium chloride​
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