The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Given the coordinate (15, -21) and the line 5x + 2y = 4
In order to get the point on the line 5x + 2y =4, we can a point on the line
Let x = 0
5(0) + 2y = 4
2y = 4
y = 2
The point (0, 2) is on the line.
Find the distance between the point (15, -21) and (0, 2) using the distance formula
Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Learn more here: brainly.com/question/22624745
We need to find the remainder- the sticker left over
Divide 23 stickers into 4 piles = 23/4= 5 stickers per pile and 3 stickers left over
D. She would have 3 stickers left over
Answer:
m∠DBF = 92°
Step-by-step explanation:
The given statements tell you that points E and F are midpoints of their respective sides of the triangle. Hence EF is parallel to AB and ...
ΔABC ~ ΔEFC
That means ∠DBF ≅ ∠EFC and their measures are 92°.
Answer:
JL = 78
Step-by-step explanation:
The shorter segment is a midline, so is half the length of the longer one.
2(5x-16) = 4x +34
5x -16 = 2x +17 . . . . . divide by 2
3x = 33 . . . . . . . . . . add 16-2x
x = 11 . . . . . . . . . . divide by 3
Then segment JL is ...
JL = 4x +34 = 4(11) +34 = 44+34
JL = 78
No diagram :(
can you upload a picture so we can help out or a description? thanks!
