Answer:
Amount of input horsepower needed is 279.3 hp.
Step-by-step explanation:
if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.
Now to calculate 5% of 266 hp, we can write
266 ×
= 13.3 hp
Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.
So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp
To know more about horsepower and percentage problem:
brainly.com/question/24585630
3 and 3 1/5 because the median is always in the middle
Those should be your answers I’m pretty sure
Answer:
the coefficients of static friction is 0.577
the coefficients of fkinetic friction is 0.54
Step-by-step explanation:
given information
θ = 30°
S = 2.5 m
t = 4 s
- Static friction
F - F(friction) = 0
W sin θ = μs W cos θ
μs = sin θ/ cosθ
= tan θ
= tan 30°
= 0.577
- kinetic friction
S = 
+ 
= 0
S =
a = 
= 
= 0.3 
F - F(friction) = m a
W sin θ - μ W cos θ = m a
mg sin θ - μk mg cos θ = m a
g sin θ - μk g cos θ = a
μk = g sin θ - a / g cos θ
= 9.8 sin 30° - 0.3 / 9.8 cos 30°
= 0.54
