Find x to the nearest 10th (18x-12) a 2.7 b 8.7 c 12.7 d. 10.7

(4^4 * 4^3) / 4^5 =

when multiplying exponents with the same base, add the exponents
(4^4 * 4^3 = 4^(4 + 3) = 4^7

now we have 4^7 / 4^5

when dividing exponents with the same base, u subtract the exponents.
4^7 / 4^5 = 4^(7-5) = 4^2 <===

4 0

2 years ago

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A small pizza has an 8-in. Diameter a large pizza has a 15-in. Diameter. The pizzeria charges the same price per square inch for

vlabodo [156]

The cost of large pizza is $24.62, a small pizza has an 8-in. diameter a large pizza has a 15-in. diameter the pizzeria charges the same price per square inch for both pizzas and the small pizza cost $7.

Step-by-step explanation:

The given is,

A small pizza has an 8-inches in diameter

A large pizza has a 15-inches in Diameter

The small pizza cost $7

Step:1

Area of smaller pizza,

$Area, A_{S} = \pi r^{2}$ ...................................(1)

Where, r - Radius of small pizza

From given, $r=\frac{d}{2}$

$= \frac{8}{2}$

r = 4 inches

Equation (1),

$A_{S} = \pi 4^{2}$

$=(3.14)(16)$ ( ∵ $\pi$ =3.14 )

$= 50.24$ Square inches

Step:2

Area of smaller pizza,

$Area, A_{L} = \pi r^{2}$ ...................................(1)

Where, r - Radius of small pizza

From given, $r=\frac{d}{2}$

$= \frac{15}{2}$

r = 7.5 inches

Equation (1),

$A_{S} = \pi 7.5^{2}$

$=(3.14)(56.25)$ ( ∵ $\pi$ =3.14 )

$= 176.625$ Square inches

Step:3

Cost of pizza per square meter,

$= \frac{Cost of small pizza}{Area of small pizza}$

$=\frac{7}{50.24}$

= $ 0.1393 per square meter

$Cost of Larger pizza = Area of Larger pizza$ × $Cost per square meter$

$= (176.625)(0.139331)$

= $24.62

Result:

The cost of large pizza is $24.62, a small pizza has an 8-in. diameter a large pizza has a 15-in. diameter the pizzeria charges the same price per square inch for both pizzas and the small pizza cost $7.

6 0

3 years ago

I need to say it in a audio recording so please make it understandable to say in words

Alborosie

Answer:

see explanation

Step-by-step explanation:

Consider perfect squares either side of 60, that is

49 < 60 < 64, thus

$\sqrt{49}$ < $\sqrt{60}$ < $\sqrt{64}$ , that is