Nobelium discovered in Berkeley California
Explanation:
The pH of a strong acid when titrated with a strong base is equal to 7 because of the formation of a neutral salt which corresponds to pH = 7.
But on the other hand,
The titration of the weak acid and strong base, the reaction taking place is:
HC₂H₃O₂ + OH⁻ ⇒ H₂O + C₂H₃O₂⁻
At the equivalence point, the pH is greater than 7 because of the conjugate base formed in the above reaction which gives OH⁻ in the solution as:
C₂H₃O₂⁻ + H₂O ⇒ HC₂H₃O₂ + OH⁻
<u>The hydroxide ions produced in the above reaction results in the pH above 7 (basic).</u>
Through manipulation of equations, we are able to obtain the equation:
![-pOH= log [ OH^{-}]](https://tex.z-dn.net/?f=-pOH%3D%20log%20%5B%20OH%5E%7B-%7D%5D%20)
Then we can transform the equation into:
![[ OH^{-}]= 10^{-pOH}](https://tex.z-dn.net/?f=%5B%20OH%5E%7B-%7D%5D%3D%2010%5E%7B-pOH%7D%20%20)
Then we are able to plug in the pOH and directly get [OH-]:
![[ OH^{-}] = 10^{-6.48}](https://tex.z-dn.net/?f=%5B%20OH%5E%7B-%7D%5D%20%3D%2010%5E%7B-6.48%7D%20)
Kekulé/Vant Hoff and Le Bel?