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Papessa [141]
3 years ago
15

Suppose "Element X" has a molar mass of 38.5 g/mol. How many atoms of Element X would be present in 2.78 mol?

Chemistry
1 answer:
slava [35]3 years ago
3 0

Answer:

16.74×10²³ atoms

Explanation:

Given data:

Number of moles of X = 2.78 mol

Number of atoms = ?

Solution:

According to Avogadro number.

1 mole of any substance contain 6.022×10²³ atoms. Thus,

2.78 mol × 6.022×10²³ atoms / 1 mol

16.74×10²³ atoms

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

You might be interested in
8. How many grams are there in 5 moles of lithium?
nikitadnepr [17]

Answer: m = n·M = 34.7 g

Explanation:

M(Li) = 6.941 g/mol, n = 5 mol

6 0
3 years ago
Which substance would evaporate the fastest at room temperature? (Assume each substance has approximately the same molecular
lutik1710 [3]

Answer:

A non-polar liquid.

Explanation:

Whether a substance dissolves quickly or not depends on how strongly the molecules (or atoms of an element) of a substance are attracted to one another. These interactions between atoms and/or molecules are called intermolecular forces, or IMFs for short. There are several different ones, and these are distinguished from <em>intra</em>molecular forces which are the bonds holding atoms in the molecule together. Attached is a nice little summary of these forces to consider. Our decision lies within the fact that we must pick the substance that experiences the strongest IMF (the one with the most energy). As it turns out, a dipole in a molecule confers some charge distribution on the molecule which makes slightly positive and negative ends. These can attract each other, and it's called dipole-dipole interactions. It can technically happen in a mixture, but let's assume we're dealing with pure substances. Dipoles can only form in polar compounds however, so a non-polar liquid (which is composed of non-polar molecules), will lack these dipoles and therefore cannot form dipole-dipole interactions between the molecules. This results in only having something called dispersion forces (which really every molecule attraction has - so this is the only one). It is very weak, and since the attraction between these molecules is weak, they will tend to come apart, and evaporate. You can think of the IMFs like glue, and a weak glue will not hold the molecules together well, and they will evaporate away.

On the other hand, polar (from dipole interactions) compounds can have general dipole-dipole interactions or hydrogen-bonding interactions (which is a special type of dipole-dipole interaction). H-bonding requires a Hydrogen bonded to either a Nitrogen, Oxygen, or Fluorine to do this. The main thing, is the non-polar ones don't have a dipole, and so they can't form a good intermolecular bond and evaporate quickly.

Water can H-bond, which is why it takes so long to dry and for it to evaporate in general. Nail polish, which is really a solution of acetone, has considerably weaker dipole-dipole bonds (compared to H-bonds), and evaporates quicker than water. Hope this helps!

Note: Figure taken from Chemistry: The Molecular Nature of Matter and Change 8th edition.

3 0
3 years ago
The following reaction is found to be at equilibrium at 25 celcius: 2SO3---&gt;O2 + 2SO2 + 198kJ/mol. If the value for Kc at 25
kondaur [170]

Answer:

D.) Products are weakly favored

Explanation:

For the reaction:

2SO₃ ⇄ O₂ + 2SO₂ + 198kJ/mol

The kc is defined as:

kc = [O₂] [SO₂]² / [SO₃]²

As the kc is 8,1:

8,1 [SO₃]² =  [O₂] [SO₂]²

The products are favored 8,1 times. This is a weakly favored because the usual kc are in the order of 1x10⁴. Thus, right answer is:

D.) Products are weakly favored

I hope it helps!

4 0
4 years ago
Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
True or false: nitrogen gas behaves more like an ideal gas as the temperature increases
navik [9.2K]

Is true. Nitrogen gas behaves more like an ideal gas as the temperature increases. Under normal conditions such as normal pressure and temperature conditions , most real gases behave qualitatively as an ideal gas. Many gases such as air , nitrogen , oxygen ,hydrogen , noble gases , and some heavy gases such as carbon dioxide can be treated as ideal gases within a reasonable tolerance. Generally, the removal of ideal gas conditions tends to be lower at higher temperatures and lower density (that is at lower pressure ), since the work made by the intermolecular forces is less important compared to the kinetic energy<span> of the particles, and the size of the molecules is less important compared to the empty space between them. </span><span>The ideal gas model tends to fail at lower temperatures or at high pressures, when intermolecular forces and intermolecular size are important.</span>

5 0
3 years ago
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