Question

What is the surface area of the regular pyramid below?

Answer 1

ANSWER

B. 700 units^2

EXPLANATION

The surface area of the pyramid is the area of the four triangular faces plus the area of the square base.

The area of the four triangular faces is

$= 4 \times \frac{1}{2} \times bh$

We substitute b=14 and h=18.

$= \frac{1}{2} \times 14 \times 18 \times 4$

$=504 {units}^{2}$

The area of the square base

$= {14}^{2} = 196 {units}^{2}$

The surface area of the pyramid is

$= 196 + 504 = 700 {units}^{2}$