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mixer [17]
3 years ago
11

What is the surface area of the regular pyramid below?

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

ANSWER

B. 700 units^2

EXPLANATION

The surface area of the pyramid is the area of the four triangular faces plus the area of the square base.

The area of the four triangular faces is

= 4 \times  \frac{1}{2}  \times bh

We substitute b=14 and h=18.

=  \frac{1}{2}  \times 14 \times 18 \times 4

=504 {units}^{2}

The area of the square base

=  {14}^{2}  = 196 {units}^{2}

The surface area of the pyramid is

= 196 + 504 = 700 {units}^{2}

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