Answer:

Explanation:
The products of this reaction are given by:

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

The following steps should be taken:
- balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

- balance oxygen atoms by adding 7 water molecules on the right:

- balance the hydrogen atoms by adding 14 protons on the left:

- balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

Similarly, tin(II) cation becomes tin(IV) cation:

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:


Add them together:

Adding the ions spectators:

Answer:
a) both substances are insoluble in water
b) both substances are soluble in ligroin
c) both substances suffer combustion, octane produces more CO₂ than hexene.
d) both substances are less dense than waterl, with hexene having the lowest density.
e) only hexene would react with bromine
f) only hexene would react with permanganate
Explanation:
a) both substances are non-polar and water is polar
b) both substances are non-polar and lingroin is non-polar
c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O
C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O
d) water = 997 kg/m³
ocatne = 703 kg/m³
hexene = 673 kg/m³
e) bromine test is used to detect unsaturations
f) permanganate test is used to detect unsaturations
Scientists use a Graduated Cylinder
Answer:
superstition
Explanation:
Because there is no scientific reason behind it and no connection of it to science.
The standard state of the elements Nitrogen and Oxygen are N2 and O2, knowing that they are diatomic elements. With that piece of information, the unbalanced equation for the formulation of NO2(g) should be as follows -
N2 + O2 ---> NO2
And if you include their states -
N2 ( g ) + O2 ( g ) ---> NO2 ( g )
To balance this chemical equation consider the number of reactants and products on other side of the equation. If you were to include a coefficient of one - half with respect to N2 on the reactant side, it would balance the reactants and products -