Answer:
16. What is the wavelength of a 1.32 x 10-6 eV wave?
ν = E /ν = h = 1.32 x 10-6
eV x 1.602 x 10-19
J = 3.191 331 38 x 10+8 s-1
6.626 2 x 10-34J-s 1 eV
λ = c/ν = ν = 3.00 x 108
m/ν = s = 3.00 x 108
m x 1
3.191 331 38 x 10+8 s-1
s 3.191 331 38 x 10+8 s-1
= 0.940 m
Explanation:
The answer is 0.940 m That is unless i messed something up-
<h3>
Answer:</h3>
733 g CO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O
[Given] 5.55 mol C₃H₇OH
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol C₃H₇OH → 6 CO₂
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
732.767 g CO₂ ≈ 733 g CO₂
They are called Cargo Shorts.
Answer:
C
Explanation:
I believe the answer is C.
In order to perform the experiment, in identifying the
temperature of different kinds of liquid freeze—the needed equipment is the
thermometer. It is because the thermometer is an equipment that helps in
determining a temperature. The variable in the experiment would be the
temperature as this is not consistent for the effects or outcome will likely
change.