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2 years ago

A solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12

Chemistry

2 answers:

Colt1911 [192]2 years ago

8 0

POH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

pOH = 12

Morgarella [4.7K]2 years ago

8 0

Answer:

Explanation:

p(oh) = - log ( concentration of the oh) = -log (1* 10^-12) = - (-12) = 12

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