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lidiya [134]
3 years ago
13

110) Lake Michigan holds 1.3 x 10's gallons of water. If just Chicago removed water from the lake and it

Chemistry
1 answer:
Naddika [18.5K]3 years ago
5 0

You omitted what it was raised to the power in 1.3 x 10's gallons of water,  so i will put it up as   1.3 x 10^15 gallons of water and solve with it

Answer:1,083,333 days

Explanation:

Total amount of water held by lake Michigan= 1.3 x 10^15 gallons of water

Amount of water Chicago uses per day =Chicago uses 1.2 x 10^9 gallons of water /day

Therefore,

Number of days water would last if it doesnt rain =  Total gallons provided by lake Michigan/ Total gallons consumed per day

=1.3 x 10^15 gallons of water/ 1.2 x 10^9 gallons of water /day

= 1,083,333 days

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Yakvenalex [24]

Answer:

T_2=-125.58\°C

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

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T_2=\frac{T_1P_2}{P_1}

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T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C

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