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lidiya [134]
3 years ago
13

110) Lake Michigan holds 1.3 x 10's gallons of water. If just Chicago removed water from the lake and it

Chemistry
1 answer:
Naddika [18.5K]3 years ago
5 0

You omitted what it was raised to the power in 1.3 x 10's gallons of water,  so i will put it up as   1.3 x 10^15 gallons of water and solve with it

Answer:1,083,333 days

Explanation:

Total amount of water held by lake Michigan= 1.3 x 10^15 gallons of water

Amount of water Chicago uses per day =Chicago uses 1.2 x 10^9 gallons of water /day

Therefore,

Number of days water would last if it doesnt rain =  Total gallons provided by lake Michigan/ Total gallons consumed per day

=1.3 x 10^15 gallons of water/ 1.2 x 10^9 gallons of water /day

= 1,083,333 days

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