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3 years ago

When two forces are _____ there is a change in position or motion

Chemistry

2 answers:

Dahasolnce [82]3 years ago

7 0

The answer is unbalanced!

kogti [31]3 years ago

6 0

That would be 'unbalanced.' Hope it helps!

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Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a

klio [65]

i have the same question idk the anwser tho

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3 years ago

Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3

Margarita [4]

Answer: The rate law for the reaction is $\text{Rate}=k'[H+][H_2O_2][Br^-]$

Explanation:

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

$2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O$

The intermediate reaction of the mechanism follows:

Step 1: $H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}$

Step 2: $H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}$

Step 3: $HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[H_3O_2^+][Br^-]$ ......(1)

As, $[H_3O_2^+]$ is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for $[H_3O_2^+]$ from step 1, we get:

$K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}$

$[H_3O_2^+]=K[H^+][H_2O_2]$

Putting the value of $[H_3O_2^+]$ in equation 1, we get:

$\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]$

Hence, the rate law for the reaction is $\text{Rate}=k'[H+][H_2O_2][Br^-]$

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3 years ago

A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centr

IRISSAK [1]

<h3>Answer;</h3>

 = 48,828.125 mi/hr²

<h3>Explanation and solution;</h3>

Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path.

Centripetal acceleration is given by; V²/r ;

V = 125 mi/h and r = 0.320 miles

Thus; centripetal acceleration = 125²/0.320

=15625/0.320

 = 48,828.125 mi/hr²

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Compare a crystal lattice with a molecule. What does the formula unit Al(OH)3 tell you about the compound aluminum hydroxide?

olasank [31]

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ASAP PLEASE HELP ASAP

Salsk061 [2.6K]

swift to hear, slow to speak

Explanation:

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3 years ago