Answer:
(part A) A≈ 50.27m²
(part B) C≈4m
Hope this helps have a great rest of the day, or night!! :))
I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.
First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:
1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)
2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).
3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).
4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)
Answer:
to number one you played 4.5 percent income tax to number two shes gonna pay 36.75
6a² + 7ax - 3x²
6a² + 9ax - 2ax - 3x²
3a(2a) + 3a(3x) - x(2a) - x(3x)
3a(2a + 3x) - x(2a + 3x)
(3a - x)(2a + 3x)
<h2>
Answer:</h2>
is 3 ohms
<h2>
Step-by-step explanation:</h2>
In a circuit containing two resistors and connected together in parallel, the total resistance is given by;
---------(i)
<em>Make </em><em> subject of the formula;</em>
=>
=>
=> ---------------(ii)
From the question,
= 6Ω
= 2Ω
Substitute these values into equation (ii) as follows;
=>
= 3Ω
Therefore, the value of = 3 ohms or = 3Ω