Answer:
In first equation if we put the value of x and y (x=2,y=2)than,
3x+y=8
3×x+y=8
3×2+2=8
6+2=8
8=8
in second equation the value of x=2,y=1
x2+xy=6
x2+x×y=6
4+2×1=6
4+2=6
6=6
So 4 inches diameter result the radius is 4/2 = 2 inches
area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared
volume = area of base *height
V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed
hope this will help you
I believe you meant: Use completing the square to determine the center and radius of the circle represented by this equation: <span>X^2+y^2-10x+6y=15
x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
(x-5)^2 + (y+3)^2 = 24 = 2sqrt(6)
This circle is centered at (5,-3) and has radius 2sqrt(6).</span>
