First, turn the mixed numbers into improper fractions.
7 7/9 = 70/9
7 4/5 = 39/5
Second, find common denominators.
70/9 = 350/45
39/5 = 351/45
351/45 > 350/45
Therefore, 7 4/5 is greater.
Best of Luck!
Answer:
find the value of x that makes the denominator zero: x = 7
Step-by-step explanation:
A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).
To find the value of x at the vertical asymptote, solve the equation ...
denominator = 0
x - 7 = 0
x = 7 . . . . . . . add 7 to both sides
Both mean to factor, I've never heard of a difference
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/