D.They both contain carbon, but only nucleic acids contain phosphorous.
I believe it's D. Tell me if I am wrong.
Answer:
These are the thylakoids
Explanation:
The thylakoids which contains the chlorophyll is the primary site of photosynthesis. It is covered by layers of cell called the thylakoid membrane.These are the actual site for light dependent reaction.This membrane contains both photosytem I and ii, ATPase enzymes, and Cytochrome b6f complex.While the photosystem i and ii transfer elecrons during photosynthesis, the ATPase enzyme control the catalysis the phosphorylation of ADP to ATP needed for the light independent stage, the Cytochrome proteins acts as the ETC. involved in the transfer of electron during light dependent stage.
When thylakoids are packed together in disc shape they are refer to as Grana,(singular -granum).Each grana are linked together by intergrana.Thus two or more grana are linked by intragrana to form a single photosynthetic functioning unit.The entire structure is bath continuously by the fluid medium-Stroma.
Their stacked and disc shape is to increase the surface area available to accommodate enough ETC, needed to transport electron for chemiosmosis needed for photosynthesis.
In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. The frequency of individuals that are heterozygous for this allele is 0.32.
<h3>Hardy Weinberg Equilibrium Principle </h3>
- A stable, idealized population's constant frequency of alleles and genotypes is described by the Hardy-Weinberg equilibrium principle.
- In a sizable population, random mating, or spontaneous mutations are necessary for Hardy-Weinberg equilibrium.
The Hardy-Weinberg equation dictates that the sum of the allele frequencies for each allele at the locus must equal 1, therefore p + q = 1. The Hardy-Weinberg equation is also written as p2 + 2pq + q2 = 1, where p is the population's frequency of the "A" allele and q is that of the "a" allele.
The homozygous genotype AA frequency is represented by p2, the homozygous genotype aa frequency by q2, and the heterozygous genotype aa frequency by 2pq in the equation.
Here, q = 0.2. Because of this, p = '1- q = 1 - 0.2 = 0.8.
The population of individuals who are heterozygous will now be 2pq, or 2 * 0.8 * 0.2 = 0.32.
Hence, This indicates that the population is heterozygous with a frequency of 0.32.
To learn more about Hardy Weinberg Principle refer to:
brainly.com/question/1365714
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