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Rina8888 [55]
3 years ago
9

In international morse code, each letter in the alphabet is symbolized by a series of dots and dashes: the letter a, for example

, is encoded as "· –". what is the min- imum number of dots and/or dashes needed to represent any letter in the english alphabet?
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
Morse code is essentially the same as binary. That is, there are two "digits", a dot or a dash.

There are 26 letters in the English alphabet. Clearly, we can't just use one dot or dash, since that could only encode 2 letters at the most. We can't use two symbols because that could only encode 4 letters at the most. Similarly, 3 symbols means 2^3=8 letters at most.

We have to select the smallest power of 2 that exceeds or is equal to 26. In this case, 2^5=32>26, so we would have to use up to 5 symbols to encode each letter in the alphabet.
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\text{Hey there!}

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4 0
3 years ago
Solve this system of linear equations. Separate
Gelneren [198K]

Answer:

x 2 y -4

Step-by-step explanation:

13x = -54 -20y give it is A

-10x = 60 + 20y give it is B

A + B the sum of the left side of equation is equal to the sum of the right side of equation

13 + (-10x) = -54 -20y + 60 + 20y

3x = 60-54

3x = 6

x=2

so put the x value in A or B equation you can receive y value (B is easier)

y = -4

7 0
3 years ago
Solve this for 10 points: 2x-3y+4y+2x+9y
Mekhanik [1.2K]

Answer:

the answer . is 2y

Step-by-step explanation:

combine like terms

4 0
3 years ago
Read 2 more answers
A line passes through the points (2,4) and (5,6) .
Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points (x_1,y_1) and (x_2, y_2)

then the general form y -y_1=m(x-x_1) for linear equations where m is the slope given by:

m =\frac{y_2-y_1}{x_2-x_1}

First calculate slope for the points (2, 4) and (5, 6);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}

then, by point slope intercept form;

y-4=\frac{2}{3}(x-2)

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}

then, by point slope intercept form;

y-6=\frac{2}{3}(x-5)

Yes, the only equation of line from the given options  which describes the given line are;

y-4=\frac{2}{3}(x-2)  and y-6=\frac{2}{3}(x-5)



8 0
3 years ago
Solve 3y^{2} - (y + 2) (y - 2)
hram777 [196]

Answer:

3y^2 - (y + 2) (y - 2) = 0

<=> 3y^2 - (y^2 - 4) = 0

<=> 2y^2 + 4 =0

<=>y^2 + 2 = 0

=> Because y^2 is always equal or larger than 0, there is no real solution.

Hope this helps!

:)

8 0
3 years ago
Read 2 more answers
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