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Leona [35]
3 years ago
8

The formula to convert Fahrenheit to Celsius is C=5/9(F-32). Convert 18 degrees C to Fahrenheit. Round to the nearest degree.

Mathematics
2 answers:
storchak [24]3 years ago
8 0
That would be roughly 64 degrees Fahrenheit. 
 
kumpel [21]3 years ago
3 0

Answer:

Temperature in celcius scale to the nearest degree = 64

Step-by-step explanation:

Temperature in celcius scale = 18° C

We have the formula

C=\frac{5}{9}(F-32)

Substituting value in celcius scale.

18=\frac{5}{9}(F-32)\\\\F=64.4^OC

Temperature in celcius scale to the nearest degree = 64

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David ran on a straight track. Every time he ran 480 m, he took a break. After 2 breaks, he still had to run 120 m to complete t
umka21 [38]

Answer:

540m

Step-by-step explanation:

The distance of the track is is equal to the playground's distance.

-The total distance covered is obtained by summing 120 and the distance per break by the total number of breaks:

d=480\times 2+120\\\\=1080\ m

-The distance of the playground half the track's distance:

d_p=0.5d_t\\\\=0.5\times 1080\\\\=540\ m

Hence, the distance of the playground is 540m

4 0
3 years ago
The rate of change of the mass, A, of salt at time t is proportional to the square of the mass of salt present at time t. Initia
Brums [2.3K]

Answer:

(a) -dA/dt = kA², A₀ = 10

(b) A =10/(1+ kt)

(c) t > 60 h

Step-by-step explanation:

(a) Find the IVP

A differential equation with an initial condition y₀ = f(x₀) is called an initial value problem.

The rate of decrease of A is proportional to A², and A₀ = 10, so the IVP is

-dA/dt = kA², A₀ = 10

(b) Solve the IVP

\begin{array}{rcl}-\dfrac{\text{d}A}{\text{d}t} & = & kA^{2}\\\\\dfrac{\text{d}A}{A^{2}} & =&-k\text{d}t\\\\-\dfrac{1}{A} & = & -kt + C\\\\\dfrac{1}{A} & = & kt + C\\\\\end{array}

Apply the initial condition: A₀ = 10 (when t = 0)

\dfrac{1}{10} = C\\\\\dfrac{1}{A} = kt + \dfrac{1}{10}\\\\\dfrac{10}{A} = 10kt + 1\\\\\mathbf{A} = \mathbf{\dfrac{10}{1+ kt}}

(c) Find the time when A(t) < 1

(i) Find the value of k (A₁₀ = 4)

\begin{array}{rcl}A& =&\dfrac{10}{1+ kt}\\\\4 & =& \dfrac{10}{1 + 10k}\\\\4 + 40 k & = & 10\\\\40k & = & 6\\k & = & 0.15\\\end{array}\\\\\mathbf{A} =\mathbf{ \dfrac{10}{0.15t + 1}}

(ii) Find t when A < 1

\begin{array}{rcl}A(t) & < & 1\\\dfrac{10}{0.15t + 1} & < & 1\\\\10 & < & 0.15t + 1\\9 & < & 0.15t\\t & > & 60\\\\\end{array}\\\mathbf{A < 1} \textbf{ when }\mathbf{ t >60}

The figure below shows the graph of A vs t.

6 0
3 years ago
The temperature is 60°F. The temperature will decrease by 3°F each hours. Let h be the number of hours. When will the temperatur
lisabon 2012 [21]

Answer:

For the temperature to be below 32 F, following inequality must be met,

h\geq 9.333

Step-by-step explanation:

Let "t" be the temperature at any time.

General format of a linear equation can be given as,

y= mx + c

Where,

y ⇒ dependent variable ( in this case temperature t)

m⇒ Gradient ( the rate at which the temperature drops)

x⇒ independent variable ( hours )

c⇒ intercept ( this is the starting temperature)

Now we can substitute the given values to the above format to arrive at the equation,

t=-3h+60

We can re-arrange the equations as ,

3h=60-t

=h=20-\frac{t}{3}

We can write this as an inequality when t = 32 F

h\geq 20-\frac{32}{3}

=h\geq \frac{28}{3}

=h\geq 9.333

7 0
3 years ago
If m &lt; 0 and b &gt; 0, the graph of y = mx + b does not pass through which quadrant?
pshichka [43]

Answer: Quadrant III

Step-by-step explanation:

The slope is negative and the y-intercept is positive.

This means that it is impossible for both x and y to be negative, and thus it does not pass through <u>Quadrant III</u>

6 0
2 years ago
In Priya's math class there are 10 boys and 15 girls.what is the ratio of boys to girls in Priya's math class?Express your answe
choli [55]

The ratio is 10/15.

10/15 = 2/3

2/3 = 0.6666...

4 0
3 years ago
Read 2 more answers
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