Answer: Choice C
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
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Explanation:
Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.
Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.
Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.
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In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.
Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.
Answer: 
This is the same as writing y < (-1/2)x+3
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Explanation:
The dashed boundary line goes through (0,3) and (4,1)
Apply the slope formula for those two points
m = (y2-y1)/(x2-x1)
m = (1-3)/(4-0)
m = -2/4
m = -1/2
The slope of the dashed line is -1/2. The y intercept is 3. So we go from y = mx+b to y = (-1/2)x+3 to represent the equation of the dashed line. This is the same as writing 
We shade below the dashed line to represent the inequality . Points in the shaded region are solutions to the inequality. One example point is (0,0).
Note that we don't have "or equal to" as part of the inequality sign because we are not including points on the boundary. A solid line, rather than a dashed line, would include points on the boundary.
3x-4y+2 hahahaha its not me pep perillp ie eewewr its jwghvjbe rijwte ru
Answer:
15ft
Step-by-step explanation:
you have to add 11 and 4 to get 15
It's contingency, because for some values of p and q it's true, and for the other values, it's false.
