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3 years ago

14

What is a supplementary angle

2 answers:

Serggg [28]3 years ago

7 0

Either of 2 angles with the some of 180

VMariaS [17]3 years ago

4 0

Answer:

either of two angles whose sum is 180°.

Step-by-step explanation:

Two Angles are Supplementary when they add up to 180 degrees. They don't have to be next to each other, just so long as the total is 180 degrees

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Pachacha [2.7K]

The answer would be 237.375. To get this answer, you will first use the formula given for each unit. First, you will do the first unit by putting 8 to the third power, or basically 8x8x8. After you get the product 512, you will then do the next unit. Do that one by doing 6.5 to the third power, or as followed, 6.5x6.5x6.5. Once you get the product 274.625, you will then subtract that from 512. You will then receive the answer 237.375.

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3 years ago

Surface area of a prism please help its my last day 120 points

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Answer:

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3 years ago

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Sedbober [7]

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10) An amount of $1500.00 is invested for 3 years at rate of 2% for the first year and 5%, for

AnnyKZ [126]

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3 years ago

Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

$y_1$ is not a solution of the differential equation

$y_2$ is not a solution of the differential equation

$y_3$ is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is $y'' + y' = cos2x$

Let consider the first equation to substitute

$y_1 = cosx +sinx$

$y_1' = -sinx +cosx$

$y_1'' = -cosx -sinx$

So

$y_1'' - y_1' = -cosx -sinx -sinx +cosx$

$y_1'' + y_1' = -2sinx$

So

$-2sinx \ne cos2x$

This means that $y_1$ is not a solution of the differential equation

Let consider the second equation to substitute

$y_2 = cos2x$

$y_2' = -2sin2x$

$y_2'' = -4cos2x$

So

$y_2'' + y_2' = -4cos2x-2sin2x$

So

$-4cos2x-2sin2x \ne cos2x$

This means that $y_2$ is not a solution of the differential equation

Let consider the third equation to substitute

$y_3 = sin 2x$

$y_3' = 2cos 2x$

$y_3'' = -4sin2x$

So

$y_3'' + y_3' = -4sin2x - 2cos2x$

So

$-4sin2x - 2cos2x \ne cos2x$

This means that $y_3$ is not a solution of the differential equation

6 0

3 years ago