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Alexandra [31]
3 years ago
15

Make x the subject of the formula y=3x-5

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0
Solve for x
x=5+y/3
is this what you mean by? solve for x?
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A pharmacist has a 12% solution and a 20% solution of boric acid. How much of each should she use to make 80 grams of a 15% solu
nlexa [21]

Step-by-step explanation:

If x = the amount of 12% and y = the amount of 20%, then x + y = 80

Since we need 80 grams of 15%, 80(.15) = 12.

We are given that .12x + .20y = 12.

We can solve the first equation for x or y. Let's do x.

x = 80 - y

.12(80 - y) + .20y = 12

9.6 - .12y + .20y = 12

.08y = 2.4

y = 30

x = 80 - 30 = 50

5 0
3 years ago
Read 2 more answers
Darrien read 97 pages last week.Evan read pages last week.How many 8 my 6. pages did, the boys read?
const2013 [10]
I’m really confused about this
7 0
3 years ago
Need help with finding foci of parabola
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7 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Estes Park Corp. pays a constant $6.95 dividend on its stock. The company will maintain this dividend for the next 12 years and
Brrunno [24]
The present value of an annuity of n periodic payments of P at r% where payment is made annually is given by:

PV=P \left[\frac{1-(1+r)^{-n}}{r} \right]

Given that <span>Estes Park Corp. pays a constant dividend of P = $6.95 on its stock. The company will maintain this dividend for the next n = 12 years and will then cease paying dividends forever. If the required return on this stock is r = 10 % = 0.1.

Thus, the current share price is given by:

Current \ share \ price=6.95 \left[\frac{1-(1+0.1)^{-12}}{0.1} \right] \\  \\ =6.95\left[\frac{1-(1.1)^{-12}}{0.1} \right] =6.95\left(\frac{1-0.3186}{0.1} \right)=6.95\left(\frac{0.6814}{0.1} \right) \\  \\ =6.95(6.813)=\bold{\$47.36}

Therefore, the current share price is $47.36
</span>
5 0
3 years ago
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