Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
Step-by-step explanation:
x+y=26
x-y=9
by process of elemination
2x=35
x=17.5
17.5+y=26
y=8.5
Hello from MrBillDoesMath!
Answer:
(4/5)d + 6/5
Discussion:
2/5(3d+3) =
2(2d+3)/5 =
(4d + 6)/ 5 =
(4/5)d + 6/5
Thank you,
MrB
(13*13) + (28*28) = 953
square root = 30.8706…
31cm
D = 20
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