Answer:
0.296 J/g°C
Explanation:
Step 1:
Data obtained from the question.
Mass (M) =35g
Heat Absorbed (Q) = 1606 J
Initial temperature (T1) = 10°C
Final temperature (T2) = 165°C
Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C
Specific heat capacity (C) =..?
Step 2:
Determination of the specific heat capacity of iron.
Q = MCΔT
C = Q/MΔT
C = 1606 / (35 x 155)
C = 0.296 J/g°C
Therefore, the specific heat capacity of iron is 0.296 J/g°C
Answer: A. -396 kJ
Explanation:
The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Reversing the reaction, changes the sign of 

On multiplying the reaction by 2, enthalpy gets multiplied by 2:

Thus the enthalpy change for the reaction
is -396 kJ.
Answer:
<h3>The answer is 6 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 15 g
volume = 2.5 mL
We have

We have the final answer as
<h3>6 g/mL</h3>
Hope this helps you
Answer:
1. Mosely arranged the elements based on the increasing number of protons, atomic number.
2. According to Moseley, similar properties recur periodically when elements are arranged according to increasing atomic number. Atomic numbers, not weights, determine the factor of chemical properties. Mendeleev ordered his elements in order of their relative atomic mass, and this gave him some problems.
Explanation:
Answer:
B.
Explanation:
ive done this before trust