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Lostsunrise [7]
3 years ago
5

In a chemical reaction, one or more substances called __________ are combined or broken down to form ___________. products; reac

tants products; compounds reactants; products reactants; elements
Chemistry
1 answer:
Eddi Din [679]3 years ago
7 0
The correct response should be reactants;products
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What r variable's :) :) :) :) :)
zhannawk [14.2K]

Answer: an element, feature, or factor that is liable to vary or change.

"there are too many variables involved to make any meaningful predictions"

Explanation:

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My question is what is a cell?
frez [133]

The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.

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3 years ago
The electron dot diagram for an atom of carbon has how many pair(s) of electrons and how many unpaired electrons
krok68 [10]

Answer:

The resultant structure is shown below. This structure contains four shared pairs of electrons, which are located on all four "sides" of carbon's electron dot structure. Each of these shared pairs was created by pairing one of carbon's unpaired electrons with an unpaired electron from chlorine.

Explanation:

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3 years ago
N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
3 years ago
How many grams of C6H12O6 are needed to be dissolved in water to make 100. grams of a 250. ppm solution?
Vesna [10]

Answer:

0.025 g C6H12O6

Explanation:

ppm = (g solute/ g solution)* 10^6

g solute= (ppm * g solution)/ 10^6

g solute = (250 ppm * 100 g)/10^6

g solute=0.025 g C6H12O6

4 0
3 years ago
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