Answer:
The molar solubility of lead bromide at 298K is 0.010 mol/L.
Explanation:
In order to solve this problem, we need to use the Nernst Equaiton:
![E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}](https://tex.z-dn.net/?f=E%20%3D%20E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D)
E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.
At equilibrium, E = 0, therefore:
![E^{o} = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] = log[ox] - \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] - \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 - \frac{2x5.45x10^{-2} }{0.0591}}\\\\](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20%20%3D%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D%20%5C%5C%5C%5Clog%20%5Cfrac%7B%5Box%5D%7D%7B%5Bred%5D%7D%20%3D%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%20%5C%5C%5C%5Clog%5Bred%5D%20%3D%20%20log%5Box%5D%20-%20%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%5C%5C%5C%5C%5Bred%5D%20%3D%2010%5E%7B%20log%5Box%5D%20-%20%20%5Cfrac%7BnE%5E%7Bo%7D%20%7D%7B0.0591%7D%7D%20%5C%5C%5C%5C%5Bred%5D%20%3D%2010%5E%7B%20log0.733%20-%20%20%5Cfrac%7B2x5.45x10%5E%7B-2%7D%20%20%7D%7B0.0591%7D%7D%5C%5C%5C%5C)
[red] = 0.010 M
The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.
Answer:The elements have the same number of electrons in the outer ring so they react with the same substances
Answer:
Explanation:
Both Diet Soda and regular soda contain sweeteners.
When a solute is dissolved in solution, the solution undergoes *freezing point depression* it freezing point reduces. The magnitude of freezing point depression is directly proportional to the amount of solute in a solution.
Since soda Both regular or diet soda contains more solute than water , their freezing point is will consequently be lower than water
Answer:
A change in pH in the protein habitat can modify its ionic bonds because because the chemical equilibrium shifts to one side or the other depends on the modification
Explanation:
The pH influences the charge acquired by the acidic and basic groups present in the molecules. Proteins usually have groups with characteristics of acid or weak base. Therefore, they are partially ionized in solution coexisting in equilibrium different species.
The degree of ionization of the different functional groups is in relation to the pH of the medium in which they are found, since the H3O + and OH- species are part of the equilibrium situation. Therefore, according to the pH, each group with characteristics of weak acid or base present in the molecule will be ionized to a lesser or greater extent. There are extreme situations where the balance has been totally displaced in one direction, for example: under very high pH conditions (low concentration of H3O +) weak acids are considered fully ionized, so the functional group will always have an electric charge. The same goes for the bases at very low pH values. In other equilibrium situations, species of the same molecule with different load will coexist in the solution, due to the pH value of the medium in which it is found.
Answer:
7.146
Explanation:
use the equilibrium equation
