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2 years ago

What do you need to know about two figured to be convinced that the two figures are congruent?

1 answer:

5 0

It depends on what the figure looks like. You could have SSS is If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent. As you can see, the SSS Postulate does not concern itself with angles at all.
SAS is have two triangles where we know two angles and the included side are equal.
ASA If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent
Idk what the figures you are talking about but I gave u some for triangles. If you comment back I can help u if you give me the figures you are talking about

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A rectangular prism has a length of 4 ft, a width of 2 ft, and a height of 3 ft. What is the capacity of container

KIM [24]

Answer:

Step-by-step explanation:

4 x 2 = 8 so 8 x 3 = 24

8 0

2 years ago

Solve: Square root of 108 + square root of 3

Gre4nikov [31]

Answer:

12.124355653

Step-by-step explanation:

don't know if you need to round but square root of 108 is 10.3923048454 and square root of 3 is 1.73205080757

5 0

3 years ago

tatiyna

Answer:

The volume of P is 1728 cubic yards.

Step-by-step explanation:

For similar shapes, the ratio of volumes are defined as:

$\frac{V_{1} }{V_{2}}$ = $(\frac{h_{1} }{h_{2}}) ^{3}$

where h1 and h2 are the heights of each pyramid respectively.

We know that the scale factor of P to Q is 6:1 i.e. the ratio of heights is also 6:1. And the volume of Q is given as 8 cubic yards. so, using the relation defined above we can write:

$\frac{V_{P} }{V_{Q}}$ = $(\frac{h_{P} }{h_{Q}}) ^{3}$

$\frac{V_{P} }{8}$ = $(\frac{6}{1} )^{3}$

Vp = 6³ * 8

= 216 * 8

Vp = 1728 cubic yards

The volume of P is 1728 cubic yards.

8 0

2 years ago

1( m² + 15m + 56) = (____) (m+8) 2 a² +5ab + 6b²=(a +2b (_____) pastor po

Nutka1998 [239]

Step-by-step explanation:

${m}^{2} + 15m + 56 = ( \: \: \: \: \: )(m + 8) \\ solution \\ \: \: taking \: lhs \\ = {m}^{2} + 15m + 5 \\ = {m}^{2} + (7 + 8)m + 56 \\ \: \: \: \: = {m}^{2} + 8m + 7m + 56 \: \: \\ now \: taking \: common \: factor \\ m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\ {m}^{2} + 15m + 56 = (m + 7)(m + 8)$

${a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( \: \: \: \: \: \: \: \: ) \\ solution \\ taking \: \: lhs \\ = {a}^{2} + 5ab + 6 {b}^{2} \\ = {a}^{2} + ( 3+ 2)ab + 6 {b}^{2} \\ = {a}^{2} + 3ab + 2ab + 6 {b}^{2} \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( a + 3) ans$

this may help you(:

7 0

2 years ago

I need help with this , please help

PIT_PIT [208]

Start with the 3 then move on

3 0

3 years ago