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hoa [83]
3 years ago
7

Which statement best describes the intermolecular forces between N2

Chemistry
1 answer:
Ad libitum [116K]3 years ago
8 0

<u>Answer:</u>

<em>D. Van der Waals forces are the strongest force between N2  molecules, and hydrogen bonding is the strongest between NHS  molecules</em>

<em></em>

<u>Explanation:</u>

Vander Waal’s forces are the forces which arises due to disturbance in the electron density of the molecule.

These are usually found in non polar molecules. Hence N2 is said to exhibit this force.

The bond between H atom and highly electronegative atom like N, O and F is said to be Hydrogen Bonding.

Molecules like HF, H2O, NH3 all have Hydrogen bonding in it.

The order of strength of the various intermolecular forces are as follows:

<em>Metallic bond < Ionic bond > covalent bond (Intra molecular) > hydrogen bonding > dipole-dipole forces > Vander Waals forces   </em>

<em> </em>

<u><em>Out of these Vander Waals is the weakest force we can see. </em></u>

<u><em></em></u>

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The electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.

<h3></h3><h3>What is periodic table?</h3>

Periodic table is defined as a tabular approach of showing the items so that they appear in the same vertical column or group when their attributes are similar. Phosphorus is the oldest chemical element, and hassium is the newest. Please take note that, unlike in the Periodic system, the elements do not exhibit their natural relationships with one another.

The elements that make up group 17 of the periodic table are the halogens. They are nonmetals that are reactive, such as iodine, bromine, chlorine, and fluorine. Halogens are non-metals that are very reactive. These substances share a lot of characteristics with one another.

Thus, the electron configuration of alkali metals would then resemble those of group 17 of the periodic table in the compounds they form.

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1 year ago
Read 2 more answers
Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe
Illusion [34]

Answer:

a. Kp=1.4

P_{A}=0.2215 atm

P_{B}=0.556 atm

b.Kp=2.0 * 10^-4

P_{A}=0.495atm

P_{B}=0.00995 atm

c.Kp=2.0 * 10^5

P_{A}=5*10^{-6}atm

P_{B}=0.9999 atm

Explanation:

For the reaction  

A(g)⇌2B(g)

Kp is defined as:

Kp=\frac{(P_{B})^{2}}{P_{A}}

The conditions in the system are:

          A                    B

initial   0                1 atm

equilibrium x       1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.    

Replacing these values in the expression for Kp we get:

Kp=\frac{(1-2x)^{2}}{x}

Working with this equation:

x*Kp=(1-2x)^{2} - -> x*Kp=4x^{2}-4x+1- - >4x^{2}-(4+Kp)*x+1=0

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1

The general expression to solve these kinds of equations is:

x=\frac{-b(+-)*\sqrt{(b^{2}-4ac)}}{2a} (equation 1)

We just take the positive values from the solution since negative partial pressures don´t make physical sense.

Kp = 1.4

x_{1}=\frac{(1.4+4)+\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=1.128

x_{1}=\frac{(1.4+4)-\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=0.2215

With x1 we get a partial pressure of:

P_{A}=1.128 atm

P_{B}=1-2*1.128 = -1.256 atm

Since negative partial pressure don´t make physical sense x1 is not the solution for the system.

With x2 we get:

P_{A}=0.2215 atm

P_{B}=1-2*0.2215 = 0.556 atm

These partial pressures make sense so x2 is the solution for the equation.

We follow the same analysis for the other values of Kp.

Kp=2*10^-4

X1=0.505

X2=0.495

With x1

P_{A}=0.505atm

P_{B}=1-2*0.505 = -0.01005 atm

Not sense.

With x2

P_{A}=0.495atm

P_{B}=1-2*0.495 = 0.00995 atm

X2 is the solution for this equation.  

Kp=2*10^5

X1=50001

X2=5*10^{-6}

With x1

P_{A}=50001atm

P_{B}=1-2*50001=-100001atm

Not sense.

With x2

P_{A}= 5*10^{-6}atm

P_{B}=1-2*5*10^{-6}= 0.9999 atm

X2 is the solution for this equation.  

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