Answer:
V₂ = 1866.32 mL
Explanation:
Given data:
Initial temperature = 27.8°C (27 + 273.15 K = 300.15 k)
Initial volume = 1500 mL
Final volume = ?
Final temperature = 100.0°C (100.0 + 273.15 K = 373.15 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
1500 mL / 300.15 k = V₂ / 373.15 K
V₂ = 1500 mL× 373.15 K/ 300.15 k
V₂ = 560175 mL. K /300.15 k
V₂ = 1866.32 mL
Answer:
There are 70 grams of KOH
Explanation:
First, we calculate the weight of 1 mol of KOH:
Weight 1 mol KOH: Weight K + Weight 0 + Weight H= 39g+ 1g+ 16g= 56 g/mol
1 mol-------56 g KOH
1,25 mol----x= (1,25 molx56 g KOH)/1 mol= <em>70 g KOH</em>
certin greenhouse gasses poke hole in our Ozone layer which can lead to higher temps and bigger storms and longer droughts
1.) Particle B has a greater kinetic energy because when a particle is at higher temperature it contains more energy.
2.) Diagram B best shows the overflow of heat between the particles. It does because of the enclosed space that it is in and how it will circulate in it.
3.) Heat is transferred between object A and B by having object B (warmer) make a reaction with object A (colder).
