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kirill [66]
3 years ago
15

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Chemistry
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

i don't understand your question.

Explanation:

Too confusing to read

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What happens to the energy absorbed during an endothermic reaction
LuckyWell [14K]

Answer:

more energy is absorbed when the bonds in the reactants are broken

4 0
2 years ago
K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.
amid [387]

<em>Answer:</em>

  • Conc. of K+ ions = 0.90 M
  • Coc. of SO4∧-2 = 0.45 M

<em>Explanation:</em>

<em>Data Given:</em>

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆   2K+   +   SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

                      K2SO4  :  K+                                          K2SO4  : SO4∧-2

                          1      =     2                                                   1     =    1

                     0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450

<em> Result:</em>

Conc. of potassium ion will be 0.90M    

Coc. of sulphate ions will be 0.45 M

8 0
3 years ago
25.88 grams of tin (ll) phosphate reacts with 31.73 grams of zinc.
Dovator [93]

Explanation:

Zn + Sn3(PO4)4 = Zn3(PO4)2 + Sn - Balanced Chemical Equation

4.3 is limiting

is the answer

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6 0
2 years ago
Topics: Fundamentals of electrochemistry; Electrochemical cells
irina1246 [14]

Answer:

how to help people that helps

5 0
2 years ago
Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M

5 0
3 years ago
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