All categories

3 years ago

Jvjvjvjvjvjbjbkbjbjjbjb

Chemistry

1 answer:

Sladkaya [172]3 years ago

8 0

Answer:

i don't understand your question.

Explanation:

Too confusing to read

You might be interested in

What do all organic substances have in common

motikmotik

All organic substances contain carbon atoms.

6 0

3 years ago

Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75

MissTica

The molarity of formic acid is 100 mM or $100\times 10^{-3}M$ . The dissociation reaction of formic acid is as follows:

$HCOOH\leftrightharpoons HCOO^{-}+H^{+}$

The expression for dissociation constant of the reaction will be:

$K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}$

Rearranging,

$[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}$

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

$[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M$

Similarly, $pK_{a}=3.75$ thus,

$[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M$

Putting the values,

$[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M$

Therefore, the concentration of formate will be 0.2511 M.

4 0

3 years ago

Reasons why water is a good cooling agent in machines

Fiesta28 [93]

Answer:

one reason is, Water is a very good liquid for cooling things down, for one thing there is plenty of it and it has also got a high specific heat capacity. This means that it can absorb a large amount of heat energy without getting too hot.

will not heat up or cool down very fast

Water has a high value of latent heat of vapourization so it has cooling properties.
hope this helps you. :)

Explanation:

4 0

1 year ago

Water (H2O) is not found on the periodic table because water is it an _.

omeli [17]

It does not consist of a single element

Hope I helped! ( Smiles )

3 0

3 years ago

Read 2 more answers

At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i

olganol [36]

Answer:

$K_c=0.0867$

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.760}{1.50\ L}$

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

$\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}$