All categories

3 years ago

How can you use negative numbers to represent real-world problems

1 answer:

8 0

Hi , basically when we want to use negative numbers in real world problems , we should always put words like decrease , drops , less , because those words describe an explicit situation that describes subtraction , for example Ana is playing soccer with her friends , her score is less than 0 because she has been trying to mark a goal but she is unable to do it . The score of Ana is -5 , the score of her friend is -2 .

<span />

You might be interested in

Assign two variables for each problem, and write the equations. Do not solve.

GalinKa [24]

Call the amount of pineapple "P', and the amount of gingerale "G".

We know that a mix of pineapple and gingerale makes 200 cups. So:
$P+G=200$

We also know that double the pineapple (i.e. 2P) and triple the gingerale (i.e. 3G) makes 420 cups. So:
$2P+3G=420$

We can now solve by substitution:
$2P+3(200-P)=420$
$2P+600-3P=420$
$-P=-180$
$P=180$

$180+G=200$
$G=20$

For 420 cups we need 2P=360 cups of pineapple and 3G=60 cups of gingerale]

3 0

3 years ago

The bearing of a plane from an airport is 65 degrees

AleksAgata [21]

Answer:

115

idk how to explain this but u just use the protractor

8 0

3 years ago

Read 2 more answers

What is the input value for which f(x)=3

Zina [86]

Answer:

-3

Step-by-step explanation:

Because f(x) = y so when y=3 what is input value (x)

When y is 3 x is -3

8 0

2 years ago

Read 2 more answers

Use the following for long division x^2+3x+1sqrt 3x^4+7x^3+2x^2+13x+5

goldenfox [79]

In plain text, it is appropriate to express the division using a division bar (/) and parentheses around the numerator and denominator:
(3x^4 +7x^3 +2x^2 +13x +5)/(x^2 +3x +1)

It is best to reserve the square root symbol (√) for an actual square root.

Your quotient is
3x^2 -2x +5

8 0

3 years ago

1. A student took 60 minutes to answer a combination of 20 multiple-choice and extended-response questions. She took 2 minutes t

Darina [25.2K]

Answer:

1) m=15 and r =5

2) 4 and 2 ml

3) x= 0.5 and y = -1

Step-by-step explanation:

given that m multiple choice questions and r extended response questions.

Also given that a) m+r = total no of questions =20 ... i and

2m+6r = total time taken = 60 ... ii

b) Divide second equation by 2, m+3r = 30 ... iii

m+r = 20 ... i

Subtract to get 2r =10 or r =5

m = 20-5 = 15

Verify: m+r = 15+5 =20

and 2m+6r = 30+30 = 60 minutes.

Hence verified

--------------------------------------

2) Let a litres of 20% solution and b litres of 50% solution be mixed

a) Then total volume = 6 ml = a+b ... i

Resulting solution = 30% of 6 ml = 1.8 = 0.2a+0.5b ... ii

b) Solve i and ii

b = 6-a: substitute in ii.

0.2a + 3-0.5a = 1.8

Or a = 4 ml and b = 2ml

Verify: Total volume = a+b =6ml and

concentration = 0.2(4)+0.5(2) = 1.8 = 30% of 6 ml.

Thus verified

---------------------------------

3) 2x-3y=4 ...i

2x-5y =6... ii

Because x term has the same coefficient in both the equations, elimination is easier.

i-ii gives 2y =-2 or y =-1

Substitute in i, 2x+3 =4 or x = 0.5

So answer is x = 0.5 and y =1

6 0

3 years ago