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3 years ago

How can you use negative numbers to represent real-world problems

1 answer:

8 0

Hi , basically when we want to use negative numbers in real world problems , we should always put words like decrease , drops , less , because those words describe an explicit situation that describes subtraction , for example Ana is playing soccer with her friends , her score is less than 0 because she has been trying to mark a goal but she is unable to do it . The score of Ana is -5 , the score of her friend is -2 .

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Solve log base 6 (x-6) - log base 6 (x + 4) = 2

Ray Of Light [21]

Answer:

no solutions

Step-by-step explanation:

Since the two terms have the same base, we are able to use the rule for subtracting logarithms:

$log_{b}(x) - log_{b}(y) = log_{b}(\frac{x}{y} )$

Therefore, the equation can be written as:

$log_{6}(\frac{x-6}{x+4} )=2$

By using the definition of a logarithm we can say that:

$\frac{x-6}{x+4} = 6^{2}\\\frac{x-6}{x+4} = 36\\x -6 = 36x+144\\35x = -150\\x =-\frac{30}{7}$

When plugging this solution in, you find that the term $log_{6}(x-6)$ has x-6 evaluate to a number less than 0. This is not included in the domain of log functions, so $-\frac{30}{7}$ is not a valid solution. This means that there are no solutions.

4 0

1 year ago

two bird populations were studied and formulas were developed for each populations growth. the populations p1 and p2 are given b

STatiana [176]

Answer:

$20 e^{k*10} = 60 e^{0.2*10}$

We can divide both sides by 20 and we got:

$e^{10k}= 3 e^{2}$

Now we can appply natural log on both sides and we got:

$10 k = ln(3e^2)$

Now we can divide both sides of the equation by 10 and we got:

$k = \frac{ln(3e^2)}{10}= 0.30986$

So then the aproximate value of k is 0.30986 and rounded would be 0.31

Step-by-step explanation:

We have the following two expression:

$p_1 = 20 e^{kt}$

$p_2 = 60 e^{0.2t}$

We know that the two populations were equal 10 years after the start of the study, so then we can create the following equation:

$20 e^{k*10} = 60 e^{0.2*10}$

We can divide both sides by 20 and we got:

$e^{10k}= 3 e^{2}$

Now we can appply natural log on both sides and we got:

$10 k = ln(3e^2)$

Now we can divide both sides of the equation by 10 and we got:

$k = \frac{ln(3e^2)}{10}= 0.30986$

So then the aproximate value of k is 0.30986 and rounded would be 0.31

6 0

3 years ago

Which of the following is not a true statement about pi?

FinnZ [79.3K]

Answer:

Option D.The ratio of the radius of a circle to its circumference

Step-by-step explanation:

Verify each statement

A) The ratio of the circumference of a circle to its diameter

The statement is True

Because

$C=\pi D$

$\pi=C/D$

B) Approximated to be 3.14

The statement is True

Because $\pi=3.14159265...$

C) Approximated to be 22/7

The statement is True

Because

$\frac{22}{7}=3.1423$

D) The ratio of the radius of a circle to its circumference

The statement is not True

Because

$\frac{r}{2\pi r}=\frac{1}{2\pi}$

4 0

2 years ago

CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!

aksik [14]

Answer:

F= 3x^2

Step-by-step explanation:

1) Multiplying exponents causes them to add, for instance if you were to multiply x^3 * x^4 the final product would be x^7. If you were to divide exponents then they would subtract.

2) Similarly in this problem you would determine the missing factor by dividing the product from -10x^3

3) Using the steps above, begin dividing.

-30x^5 / -10x^3

4) -30 divided by -10 is 3 and as mentioned in step number one, you subtract exponents whenever they are divided by each other. 5-3=2

5) Due to all of the steps mentioned above, The answer is 3x^2

6 0

3 years ago

Read 2 more answers

F (x) = 3x + 7 F (-4) = F (2) =

V125BC [204]

Answer:

f(-4)=3(-4)+7=0

f(2)=3(2)+7=13

3 0

2 years ago

Read 2 more answers