Answer:

Explanation:
The force exerted between two current-carrying wires is given by

where
is the vacuum permeability
I1 and I2 are the two currents
L is the length of the segment of wire on which we want to calculate the force
r is the distance between the wires
In this problem we have:

Substituting into the formula, we find:

And since the direction of the two currents is opposite, the force between the wires is repulsive.
Answer:
- 1.07 ft
Explanation:
V1 = (-5, 7, 2)
V2 = (3, 1, 2)
Projection of v1 along v2, we use the following formula
=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}
So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4
The magnitude of vector V2 is given by
= 
So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft
Thus, the projection of V1 along V2 is - 1.07 ft.
so we need to find the direction of v2
Answer:
E =17,280 J
Explanation:
Since the voltage drops linearly from 6V to 4V, the average is 5V. The energy delivered is .
V is the average of initial and fianl voltage
A is the current passing
t is the time in which current is passed
E=V*A*t = 5*0.015*(64*3600) = 17,280 J
Using momentum balance:
The 588 N mother is on the other side of the seesaw, 2.20m away from the pivot
F1 = 588 N
x1 = 2.20 m
Two of her children sat on the other side:
F2 = 256 N
x2 = 2.00 m
F3 = 412 N
x3 = unknown
F1x1 = F2x2 + F3x3
Solve for x3:
588 * 2.2 = 256 * 2 + 412 * x3
x3 = 1.90 meters away from pivot