1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
exis [7]
2 years ago
6

A 588 mother sits on one side of a seesaw, 2.20m away from the pivot. one of her two children sits 2.00m from the pivot on the o

ther side of the seesaw. If the force of gravity on her is 256N, where must the other child sit to balance the seesaw if the force of gravity on him is 412 N ?
Physics
1 answer:
erastovalidia [21]2 years ago
3 0
Using momentum balance:

The 588 N mother is on the other side of the seesaw, 2.20m away from the pivot

F1 = 588 N
x1 = 2.20 m

Two of her children sat on the other side:

F2 = 256 N
x2 = 2.00 m

F3 = 412 N
x3 = unknown

F1x1 = F2x2 + F3x3

Solve for x3:

588 * 2.2 = 256 * 2 + 412 * x3

x3 =  1.90 meters away from pivot
You might be interested in
S Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to
denpristay [2]

The diameter of the wire is 2.8 * 10^-3 m.

<h3>What is the length?</h3>

Mass of the wire = 1.0 g or 1 * 10^-3 Kg

Resistance = 0.5 ohm

Resistivity of copper = 1.7 * 10^-8 ohm meter

Density of copper = 8.92 * 10^3 Kg/m^3

V = m/d

But v = Al

Al = m/d

A = m/ld

Resistance = ρl/A

= ρl/m/ld =

l^2 = Rm/ρd

l = √ Rm/ρd

l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3

l = 1.82 m

A = πr^2

Also;

A = m/ld

A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3

A = 6.2 * 10^-5 m^2

r^2 = A/ π

r = √A/ π

r = √6.2 * 10^-5 m^2/3.142

r = 1.4 * 10^-3 m

Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m

Learn more about resistivity:brainly.com/question/14547003

#SPJ4

Missing parts;

Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?

5 0
1 year ago
I need to know which ones are physical or chemical changes.
andrezito [222]
Physical
Chemical
Physical
Chemical
Chemical
Chemical
Physical
Physical
Physical
Chemical
Chemical
Physical
Physical
Physical
Chemical
Chemical
Chemical
Chemical
Physical
Chemical
Chemical
Chemical
Chemical
Chemical
Chemical

I believe this is right but double check to make sure :)
7 0
2 years ago
If a ball rolls off a 4m high table at 7m/s, how long will it take until it hits the floor
Semenov [28]
It will take at least 0.8
3 0
3 years ago
Cual sera el caudal que lleva un rio cuando se desplaza a 200 litros cada 40 segundos
alisha [4.7K]

Answer:

Q = 5 L/s

Explanation:

To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):

Q=\frac{V}{t}

V: Volume (volumen) = 200L

t: time (tiempo) = 40 s

you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):

Q=\frac{200L}{40s}=5\frac{L}{s}

Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)

4 0
3 years ago
A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angul
zepelin [54]

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}

\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}

\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 +  \omega^2}

\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2}  }

\mathbf{\omega^2=\dfrac{39.24 }{2}}

\mathbf{\omega=\sqrt{19.62 } \ rad/sec}

\mathbf{\omega=4.429 \ rad/sec}

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

Learn more about angular velocity here:

brainly.com/question/1452612

4 0
2 years ago
Read 2 more answers
Other questions:
  • How does an airbag help protect a passenger in a car accident?
    8·2 answers
  • Location X is next to Location Y and they are both much colder than Location Z. Which statement is most likely true?
    11·1 answer
  • Air flows upward in the wick of a lantern because of the liquid property called
    14·1 answer
  • A car can be braked to a stop from the autobahn-like speed of 206 km/h in 190 m. Assuming the acceleration is constant, find its
    11·1 answer
  • 5. The boiling point of mercury is lower than<br> that of alcohol.
    8·2 answers
  • A car starts from rest and after 7.0 seconds it is moving at 42 m/s. What is the car's average acceleration?
    10·1 answer
  • Hey can someone please help answer this question?
    10·1 answer
  • Plz help me fill out this table
    12·1 answer
  • in addition to studies of the body system of corals what studies in earth science might increased scientists understanding of an
    11·1 answer
  • A very rigid material—one that stretches or compresses only slightly under large forces—has a large value of __________.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!