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ASHA 777 [7]
3 years ago
10

How many microphones are in a megaphone?

Physics
1 answer:
Rina8888 [55]3 years ago
3 0
10 to the 12th power<span> microphones = 1 megaphone</span>
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A pan of ice is placed over a flame.
AveGali [126]
A. The molecules start packed together very tightly in a solid. Then when it turns to water, the molecules can move around each other freely, but still contained. When water turns to vapor, the molecules are going crazy moving around. They are not contained at all and bounce of of each other freely.

b. The temperature rises. (ice turns to water at 33 degrees and water turns to vapor at 212 degrees)
8 0
3 years ago
An irrigation canal has a rectangular cross section. At one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, t
Irina-Kira [14]

Answer:

The depth of the water at this point is 0.938 m.

Explanation:

Given that,

At one point

Wide= 16.0 m

Deep = 3.8 m

Water flow = 2.8 cm/s

At a second point downstream

Width of canal = 16.5 m

Water flow = 11.0 cm/s

We need to calculate the depth

Using Bernoulli theorem

A_{1}V_{1}=A_{2}V_{2}

Put the value into the formula

16.0\times3.8\times2.8=16.5\times x\times 11.0

x=\dfrac{16.0\times3.8\times2.8}{16.5\times11.0}

x=0.938\ m

Hence,  The depth of the water at this point is 0.938 m.

7 0
3 years ago
Describe grafting, what are the<br> three methods?
Tanya [424]

Answer: cleft grafting, inlay grafting, four-flap grafting, and whip grafting.

Explanation:

I hope I helped , Have a great day or night . Xoxoxo.

6 0
2 years ago
Why would a flare be observed in visible light, when they are so much brighter in X-ray and ultraviolet light?
raketka [301]

Answer:

Because it radiates a spectre of frequencies, this means that it radiates in a continuous range of frequencies, ones with more intensity (like x-ray and ultraviolet) and others with less intensity (like the visible light). While most of the radiation is not in the visible range, there still is a part of the radiation in the visible spectre. And while this part is not the most intense part, the radiation is so large that we can see a very bright visible light.

3 0
2 years ago
Which of the following correctly identifies the initial direction of the force on the moving positively charged particle (i.e.,
meriva

Answer:

Explanation:

Given

Current is flowing towards right side

Considering right side i.e. +x to be positive and direction outside the paper be +k

suppose charge is below the wire and is moving towards right

v=v_0\hat{i}

magnetic field below the wire is outside the Paper using right hand thumb rule

B=B_0\hat{k}

F=q(\vec{v}\times \vec{B})

F=q(v_0\hat{i}\times B_0\hat{k})

F=-qv_0B_0\hat{j}

i.e. Force acts in Downward direction

i charge is moving towards left i.e.

v=-v_0\hat{i}

F=q(-v_0\hat{i}\times B_0\hat{k})

F=qv_0B_0\hat{j} towards upward direction

6 0
2 years ago
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