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Aleks [24]
3 years ago
6

A particle, of mass 6 kg, is in equilibrium on a rough horizontal plane under a force o-f magnitude T N, which acts at an angle

15° above the horizontal. Given the coefficient of friction between the particle and the rough horizontal plane is 0.35, what values could T take?
Physics
1 answer:
Helga [31]3 years ago
3 0

Answer:

T is less than or equal to 19 N

Explanation:

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16. For this table of data, how should the y-axis be labeled (with units)?
vampirchik [111]

Answer:

The y-axis should be labelled as W in Newtons (kg·m/s²)

Explanation:

The given data is presented here as follows;

Mass (kg)            {}        Newtons (kg·m/s²)

3.2                      {}           31.381

4.6             {}                    45.1111

6.1              {}                    59.821

7.4              {}                    72.569

9                {}                     89.241

10.4              {}                   101.989

10.9              {}                  106.892

From the table, it can be seen that there is a nearly linear relationship between the  amount of Newtons and the  mass, as the slope of the data has a relatively constant slope

Therefore, the data can be said to be a function of Weight in Newtons to the mass in kilograms such that the weight depends on the mass as follows;

W(m) in Newtons = Mass, m in kg × g

Where;

g is the constant of proportionality

Therefore, the y-axis component which is the dependent variable is the function, W(m) = Weight of the body while the x-axis component which is the independent variable is the mass. m

The graph of the data is created with Microsoft Excel give the slope which is the constant of proportionality, g = 9.8379, which is the acceleration due to gravity g ≈ 9.8 m/s²

We therefore label the y-axis as W in Newtons (kg·m/s²)

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