Answer:
Explanation:
Given that,
The mutual inductance of the two coils is
M = 300mH = 300 × 10^-3 H
M = 0.3 H
Current increase in the coil from 2.8A to 10A
∆I = I_2 - I_1 = 10 - 2.8
∆I = 7.2 A
Within the time 300ms
t = 300ms = 300 × 10^-3
t = 0.3s
Second Coil resistance
R_2 = 0.4 ohms
We want to find the current in the second coil,
The same induced EMF is in both coils, so let find the EMF,
From faradays law
ε = Mdi/dt
ε = M•∆I / ∆t
ε = 0.3 × 7.2 / 0.3
ε = 7.2 Volts
Now, this is the voltage across both coils,
Applying ohms law to the second coil, V=IR
ε = I_2•R_2
0.72 = I_2 • 0.4
I_2 = 0.72 / 0.4
I_2 = 1.8 Amps
The current in the second coil is 1.8A
The magnitude of the net displacement is 95.3 m
Explanation:
To find the magnitude of the net displacement, we have to resolve each of the two displacements into the horizontal and vertical direction first.
1st displacement is:
at 
So its components are

2nd displacement is:
at 
So its components are

Therefore, the x- and y-components of the net displacement are:

Therefore, the magnitude of the final displacement is:

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Answer:

Explanation:
From this exercise, our knowable variables are <u>hight and initial velocity </u>


To find how much time does the <u>ball strike the ground</u>, we need to know that the final position of the ball is y=0ft


Solving for t using quadratic formula


or 
<u><em>Since time can't be negative the answer is t=6.96s</em></u>
Bumper of a stationary bumper car. The momentum of the
stationary car increases. Which happens to the momentum of the moving bumper
car? It decreases. It stays the same. It is converted to inertia.
Bumper of a stationary bumper car. The momentum of the
stationary car increases. The momentum of the moving bumper car It is converted
to inertia.
Yes, the above-given statement is true
<u>Explanation:</u>
- The product of the mass x the velocity will be the same for both. Momentum is the action of a body with a particular mass through space and there is the conservation of momentum.
- Momentum is described as the mass of the object multiplied by its velocity.
- <u>Momentum (p) = Mass (M) * Velocity (v)</u>
- Therefore for two objects with many masses to have a similar momentum, then the lighter one has to be moving quicker than the heavier object.