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2 years ago

If f[6} = x ^ -2x , find: f [6} =

Mathematics

1 answer:

ASHA 777 [7]2 years ago

7 0

Answer:

1/ 6^12

Step-by-step explanation:

f[x} = x ^ (-2x)

f(6) = 6 ^ (-2*6)

= 6 ^ -12

We know the negative exponent moves it to the denominator

= 1/ 6^12

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Pls help me with this! (Links=report)

xxMikexx [17]

Answer:

XZ=12 in

Step-by-step explanation:

area of a rhombus is A=pq/2

where p=WY=15.5 and A=93 and q=XZ

93=15.5(XZ)/2

93(2)=15.5(XZ)

186/15.5=XZ

XZ=12 in

7 0

3 years ago

Two bookstores are having a sale on comic books. Main Street Books has a deal of 10 for $5.20 and Books Galore has a deal of 6 f

gizmo_the_mogwai [7]

Answer:

Books Galore has the lowest unit price

Step-by-step explanation:

if you divide main streets books, 10 ÷ $5.20 = $1.92

Books galore : 6 ÷ $3.60 = $ 1.66

5 0

2 years ago

Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

Levart [38]

Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "-1 to the fourth."

MULTIPLYING -1 by itself 4 times results in $-1\cdot-1\cdot-1\cdot-1=1$ .

Applying this logic to our original term, $3(-1)^4$ :

$3(-1\cdot-1\cdot-1\cdot-1)$
$3(1)$
$3$

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: $-5x^2$

$-5(-1)^2$

Applying the same logic from our first term:

$-5(-1 \cdot -1)$
$-5(1)$
$-5$

Third term: $2x$

$2(-1) = -2$

-3 is just -3, no influence of x.

Combining our terms, we have $3-5-2-3$ .

This comes out to be -7, hence, the value of $f(-1)$ for our function $f(x)=3x^4-5x^2+2x-3$ is -7.

Hope this helped!

4 0

3 years ago

Read 2 more answers

Oct 09, 11:40:51 AM

kumpel [21]

Get it sis 57
11 23 fhsjjdjrjr

8 0

2 years ago

A projectile was launched straight up from the ground with an initial velocity of 48 ft/s. The height of the projectile t second

alex41 [277]

Factor f(t) and you can identify the values of t for which the height is zero.
.. f(t) = -16t(t -3)

The projectile lands after 3 seconds in the air. (selection A)

8 0

3 years ago