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3 years ago

M(-3,2) is the midpoint of AP. If A has coordinates (-1,5), what are the coordinates of P?

Mathematics

1 answer:

Inessa05 [86]3 years ago

8 0

Answer:

Step-by-step explanation:

If M is midpoint of AP then:

$x_P-x_M=x_M-x_A\qquad\quad\ \wedge\qquad y_P-y_M=y_M-y_A\\\\x_P-(-3)=-3-(-1)\qquad\wedge\qquad y_P-2=2-5\\\\x_P+3=-3+1\qquad\quad\ \wedge\qquad\quad y_P-2=-3\\\\x_P=-3+1-3\qquad\quad\ \wedge\qquad\quad y_P=-3+2\\\\x_P=-5\qquad\qquad\ \wedge\qquad\qquad y_P=-1$

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(a) 23, 35, 28, 33, 5, 12, 40, 25, 20, 18, 1, 16

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3 years ago

Consider a prism with a height of 8 inches and a 14-inch by 14-inch square base, and a cylinder with a height of 10 inches and a

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Answer:

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Step-by-step explanation:

<u>The question is on volume of a prism and that of a cylinder</u>

<u>Finding the volume of the prism</u>

V=Bh where B is the base area and h is the height

Base area=14"×14"=196 inch²

height =8"

v=196×8= 1568 in³

<u>Finding volume of the cylinder</u>

v= $\pi$ r²h where r is the radius of cylinder and h is the height of cylinder

r=10/2=5 inches and h=10 inches

v=3.142×5×5×10=785.5inch³

<u>The difference in volume</u>

Difference in volume=1568-785.5=782.5inch³

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3 years ago

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liq [111]

Answer:

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Step-by-step explanation:

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3 years ago